If x(x+y) = x^2 + 8, what is the value of xy?
First, let's distribute and expand the left side of the equation.
Using the distributive property, we find that
\(x^2+xy=x^2+8\)
Now, notice that the x^2 cancels out.
\(xy = x^2 - x^2+8\\ xy=8\)
So 8 is our answer.
Thanks! :)
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