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A circus is composed of acrobats, ballerinas, clowns, and dogs. The number of acrobats and ballerinas, minus the number of clowns, is one fewer than the number of dogs. Twice the combined number of acrobats and ballerinas is five more than three times the number of clowns. If the number of dogs is one more than the number of clowns, how many people and animals belong to the circus?

 Oct 17, 2020
 #1
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a+b -c = d-1

2(a+b)=3c+5       re-arrange    a+b = (3c+5) /2

d=c+1

 

Use the two red equations in the first equation  ....then you can solve for c

    then    d = c+1         knowing    c and d   you can solve for a + b using the first and second equations

 
 Oct 17, 2020
 #2
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Actually, you cannot solve for a and b individually....but you do not need to do so

   a + b = 10      plus clowns  = 15 people   6 dogs

 
Guest Oct 17, 2020

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