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X^2+4x+21=0

 Apr 20, 2016
 #1
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\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

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 Apr 20, 2016
 #2
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Solve for x:
x^2+4 x+21 = 0

Subtract 21 from both sides:
x^2+4 x = -21

Add 4 to both sides:
x^2+4 x+4 = -17

Write the left hand side as a square:
(x+2)^2 = -17

Take the square root of both sides:
x+2 = i sqrt(17) or x+2 = -i sqrt(17)

Subtract 2 from both sides:
x = i sqrt(17)-2 or x+2 = -i sqrt(17)

Subtract 2 from both sides:
Answer: |  x = i sqrt(17)-2       or         x = -i sqrt(17)-2

 Apr 20, 2016

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