We have a triangle ABC such that AB=6, BC=8, and CA=10 If AD is an angle bisector such that D is on BC, then find the value of AD^2.
A
6 10
B 8 C
This is a 6 - 8 -10 right triange
Since AD is an angle bisector we have that
AD / DC = AB / AC
AD /DC = 6 / 10
AD/ DC = 3/5
AD = 3/ ( 3 + 5) * 8 = (3/8) (8) = 3
AD^2 = 3^2 = 9
