what is the slope, midpoint and distance of points (-2,5) and (6,-8)
slope=y1−y0x1−x0slope=−8−56−(−2))=−138
midpt=(x0+x12,y0+y12)midpt=(−2+62,5+−82)=(2,−3/2)
dist=√(x1−x0)2+(y1−y0)2dist=√(6−−2)2+(−8−5)2dist=√82+(−13)2=√64+169=√233