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what is the slope, midpoint and distance of points (-2,5) and (6,-8)

 Oct 1, 2015
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\(slope=\dfrac{y_1-y_0}{x_1-x_0}\\ slope=\dfrac{-8-5}{6-(-2))}=\dfrac{-13}{8}\)

 

\(midpt=\left(\dfrac{x_0+x_1}{2},\dfrac{y_0+y_1}{2}\right)\\ midpt=\left(\dfrac{-2+6}{2},\dfrac{5+-8}{2}\right)=(2,-3/2)\)

 

\(dist = \sqrt{(x_1-x_0)^2 + (y_1-y_0)^2}\\ dist= \sqrt{(6--2)^2 + (-8-5)^2}\\ dist=\sqrt{8^2+(-13)^2}=\sqrt{64+169}=\sqrt{233}\)

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 Oct 1, 2015

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