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If 6 is one root of x^2 - 2x + a = 0, then what is a?

 Jun 22, 2020
 #1
avatar+21951 
0

If  6  is one root, then  (x - 6)  is a factor.     So:  (x - 6)(x + ?)  =  x2 - 2x + a

 

When you add  ?  to  -6  you must get  -2,  so  ?  =  4

 

The factors are (x - 6)(x + 4)  =  x2 - 2x + 24

 Jun 22, 2020
 #2
avatar+26007 
+1

If 6 is a root , when you put in x= 6 the eq should = 0

62-2(6) +a = 0

36-12+a = 0

a = - 24

 Jun 22, 2020

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