In right triangle ABC with \(\angle B = 90^\circ\), we have \(\sin A = 2\cos A\). What is \(\cos A\)?

Guest Jun 26, 2019

#1**+2 **

__Sin a = 2 cos a__

__sin a / cos a = 2__

__arctan 2 = 63.44 degrees__

__Ooops sorry.... I gave ypu the angle, not the cos __

cos 63.44 = .447

Chris' answer below is the EXACT value..... ~ EP

ElectricPavlov Jun 26, 2019