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What is (f−g)(x)?

 

f(x)=3x^5+6x^2−5

g(x)=2x^4+7x^2−x+16

 Mar 6, 2018
 #1
avatar+129845 
+2

f(x)=3x^5+6x^2−5

g(x)=2x^4+7x^2−x+16

 

(f - g) x  =  (3x^5+6x^2−5)  - ( 2x^4+7x^2−x+16 )  =

 

3x^5 - 2x^4 - x^2 + x - 21

 

 

cool cool cool

 Mar 6, 2018

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