Find an integer N such that sqrt75 − sqrt12 is between N and N + 1. sqrt=square root
sqrt (75) = 5sqrt 3
sqrt 12 = 2sqrt 3
So
5sqrt 3 - 2sqrt 3 =
3sqrt 3 =
sqrt (3 * 3^2) =
sqrt (27)
5 < sqrt (27) < 6
