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What are the coordinates of the hole in the graph of the function f(x) ?

 

f(x)=x^2−9/x−3

 Feb 18, 2019
 #1
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+1

f(x)  =  [ x^2 - 9 ] / [ x - 3]

 

Factor the numerator

 

f(x)=  [ x + 3 ] [ x - 3 ] / [ x - 3 ]                    "cancel " the   x - 3  factors

 

f(x) =  x + 3       (1)

 

Since  x = 3 makes the original denominator 0......the "hole" occurs at this x value

 

And using (1)......the y value is   (3) + 3 =  6

 

So.....the coordinates of the "hole"   =  (3, 6)

 

 

cool cool cool

 Feb 18, 2019

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