+491 What are the coordinates of the hole in the graph of the function f(x) ?
f(x)=x^2−9/x−3
+129852 f(x) = [ x^2 - 9 ] / [ x - 3]
Factor the numerator
f(x)= [ x + 3 ] [ x - 3 ] / [ x - 3 ] "cancel " the x - 3 factors
f(x) = x + 3 (1)
Since x = 3 makes the original denominator 0......the "hole" occurs at this x value
And using (1)......the y value is (3) + 3 = 6
So.....the coordinates of the "hole" = (3, 6)
