Point O is the circumcenter of triangle ABC. The distance between O and Line AC is 7, and the distance between O and Line AB is 15. If AC=48, what is AB?
+128475 OD = 7
Since O is the circumcenter, OD is a perpendicular bisector of AC
So DA = (1/2) 48 = 24
And OA = sqrt ( OD^2 + DA^2) = sqrt (7^2 + 24^2) = sqrt (625) = 25
So triangle OAD is a 7 - 24 - 25 right triangle
And OE = 15 and is also a perpendicular bisector of side AB
So triangle OAE is a right triangle
And EA = sqrt ( OA^2 - OE^2) = sqrt ( 25^2 - 15^2) = sqrt (400) = 20
And AB is twice EA = 40
