+89 In △XYZ , XZ=11 , YZ=8 , and m∠Z=31∘ .
What is the area of the triangle?
Draw the height from X to the base YZ, it is perpendicular, bisects YZ (Now let the point where it bisects it be D)
Then ZD=YD=4
Notice also angle YXZ is bisected and angle XDZ is 90 degrees.
XD can be found (Which is the height)
Use Pythagoras theorem:
\(10.246\) is XD
Area of triangle=\(1/2*b*h\)
\(1/2*8*10.246 =40.984\)
actually it is wrong..
here is the answer : https://brainly.com/question/15099574
That site wanted me to create an account and log in. I didn't want to do that.
Hey, phoquee, a drawing would be nice. How do you pronounce your screen name?
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Here is the answer written from this site (I didn't login tho)
Answer:
The area of the triangle is 22.7 units²
Step-by-step explanation:
We can use trigonometry to find the area of an triangle if we have the length of two sides and the measure of the included angle between them, using the rule A = (a)(b)(sin C), where
a , b are two sides in the triangle
C is the angle between the sides a and b
In Δ XYZ
∵ XZ = 11 units
∵ YZ = 8 units
∵ The angle between XZ and YZ is ∠Z
∵ m∠Z = 31°
- We can use the formula of the area above
∴ A = (11)(8)(sin 31)
∴ A = 44 sin 31
∴ A = 22.6616753
- Round it the the nearest tenth
∴ A = 22.7 units²
The area of the triangle is 22.7 units²
