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# help

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4
+88

In △XYZ , XZ=11 , YZ=8 , and m∠Z=31∘ .

What is the area of the triangle?

Apr 17, 2020

#1
+1

Draw the height from X to the base YZ, it is perpendicular, bisects YZ (Now let the point where it bisects it be D)

Then ZD=YD=4

Notice also angle YXZ is bisected and angle XDZ is 90 degrees.

XD can be found (Which is the height)

Use Pythagoras theorem:

\(10.246\) is XD

Area of triangle=\(1/2*b*h\)

\(1/2*8*10.246 =40.984\)

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Apr 17, 2020
#2
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actually it is wrong..

here is the answer : https://brainly.com/question/15099574

Guest Apr 17, 2020
#3
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That site wanted me to create an account and log in.  I didn't want to do that.

Hey, phoquee, a drawing would be nice.  How do you pronounce your screen name?

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Guest Apr 17, 2020
#4
+1

Here is the answer written from this site (I didn't login tho)

The area of the triangle is 22.7 units²

Step-by-step explanation:

We can use trigonometry to find the area of an triangle if we have the length of two sides and the measure of the included angle between them, using the rule A =  (a)(b)(sin C), where

a , b are two sides in the triangle
C is the angle between the sides a and b
In Δ XYZ

∵ XZ = 11 units

∵ YZ = 8 units

∵ The angle between XZ and YZ is ∠Z

∵ m∠Z = 31°

- We can use the formula of the area above

∴ A =   (11)(8)(sin 31)

∴ A = 44 sin 31

∴ A = 22.6616753

- Round it the the nearest tenth

∴ A = 22.7 units²

The area of the triangle is 22.7 units²

Guest Apr 17, 2020