What is the perimeter of a rhombus with diagonals of lengths 12 and 16 units?
1/2 the length of each diagonal will form two legs of a right triangle
And the side of the rhombus will be the hypotenuse
So....the perimeter is 4 times this hypotenuse length
4 sqrt ( 6^2 + 8^2) =
4 sqrt ( 36 + 64) =
4sqrt (100) =
4 * 10 =
40 units
