+0  
 
0
205
2
avatar+492 

Help.

NotTheSmartest  Mar 7, 2017

Best Answer 

 #1
avatar+7155 
+6

I remember doing these D:

 

The slope of AB must match the slope of CD.

The slope of BC must match the slope of AD.

 

Slope of AB =  \(\frac{-1-6}{-5+9}=-\frac{7}{4}\)

Slope of CD = \(\frac{5+2}{-1-3}=-\frac{7}{4}\)

 

Slope of BC = \(\frac{6-5}{-9+1}=-\frac{1}{8}\)

Slope of AD = \(\frac{-1+2}{-5-3}=-\frac{1}{8}\)

 

So far so good. We have just shown that this is a parallelogram at least.

In order for it to be a rhombus:

 

The slope of BD must be the negative reciprocal of the slope of AC.

 

Slope of BD = \(\frac{6+2}{-9-3}=-\frac{8}{12}=-\frac{2}{3}\)

Slope of AC = \(\frac{-1-5}{-5+1}=\frac{-6}{-4}=\frac{3}{2}\)

 

Everything checks out. This figure is infact a rhombus. :)

hectictar  Mar 7, 2017
 #1
avatar+7155 
+6
Best Answer

I remember doing these D:

 

The slope of AB must match the slope of CD.

The slope of BC must match the slope of AD.

 

Slope of AB =  \(\frac{-1-6}{-5+9}=-\frac{7}{4}\)

Slope of CD = \(\frac{5+2}{-1-3}=-\frac{7}{4}\)

 

Slope of BC = \(\frac{6-5}{-9+1}=-\frac{1}{8}\)

Slope of AD = \(\frac{-1+2}{-5-3}=-\frac{1}{8}\)

 

So far so good. We have just shown that this is a parallelogram at least.

In order for it to be a rhombus:

 

The slope of BD must be the negative reciprocal of the slope of AC.

 

Slope of BD = \(\frac{6+2}{-9-3}=-\frac{8}{12}=-\frac{2}{3}\)

Slope of AC = \(\frac{-1-5}{-5+1}=\frac{-6}{-4}=\frac{3}{2}\)

 

Everything checks out. This figure is infact a rhombus. :)

hectictar  Mar 7, 2017
 #2
avatar+87333 
+5

Well-presented, hectictar....!!!

 

 

cool cool cool

CPhill  Mar 7, 2017

2 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.