+0

help

0
48
2

What is the sum of the angle measures of a 38-gon?​

Jan 17, 2020

#1
+107405
0

I assume you mean the interior  angles of  a regular  38-gon

One interior angle  measures

(36/38) (180)  ≈ 170.53°

So...the sum of these angles = 38 * (170.53)  ≈   6480.14°

Jan 17, 2020
#2
+24093
+3

What is the sum of the angle measures of a 38-gon?​

You can divide the polygon into 38-2 triangles. Each triangle has 180 degrees.

So the sum is $$(38-2)*180^\circ = \mathbf{6480^\circ}$$

Jan 17, 2020