What is the sum of the angle measures of a 38-gon?
I assume you mean the interior angles of a regular 38-gon
One interior angle measures
(36/38) (180) ≈ 170.53°
So...the sum of these angles = 38 * (170.53) ≈ 6480.14°
You can divide the polygon into 38-2 triangles. Each triangle has 180 degrees.
So the sum is \((38-2)*180^\circ = \mathbf{6480^\circ}\)
