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Help.

 Jan 8, 2018
 #1
avatar+101870 
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 l 3x  +  2  l  =  2

 

We have two equations here

 

3x +  2  =  2                      3x  +  2   =   - 2

   

  Subtract  2 from both sides

 

3x   =  0                             3x   =   - 4

 

Divide  both sides by 3

 

x  = 0                              x  =   -4/3

 

 

 

f(x)  =  x^2  -2x  +  2

 

The  domain  is all real numbers

To  find the range  we  need  to plug   -b/ [2a]  into the function where  b  =  -2   and  a  = 1

So....   -b/ [2a] =  2 / [2 * 1 ]  =  2/2  = 1    ,.....and this is the x coordinate of the vertex

So....the y coordinate of the vertex is

f(1)  =  (1)^2  - 2(1)  +  2    =  1

This parabola points upward  so the vertex  is  (1,1)

 

And  y = 1  is the low point on the function

So.....the range  is  [1, infinity )

 

The  first answer is correct

 

 

cool cool cool

 Jan 8, 2018

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