+0  
 
0
278
8
avatar+3696 

Help.

NotSoSmart  Dec 29, 2017
 #1
avatar+502 
0

WTH??

Rauhan  Dec 29, 2017
 #2
avatar+3696 
0

Lol i'm waiting for CPhill.. he'll know how to explain it down to me.

NotSoSmart  Dec 29, 2017
 #4
avatar+502 
0

by 'WTH' i thought u were trolling but there was actually a question, lemme have a look at it.

Rauhan  Dec 29, 2017
 #3
avatar+3277 
+3

For number 26, I'm getting (A), 5....

tertre  Dec 29, 2017
 #6
avatar+3696 
+1

Alright thanks

NotSoSmart  Dec 29, 2017
 #5
avatar+502 
+1

25 is a messed up question but for 26 the answer is 5

Rauhan  Dec 29, 2017
 #7
avatar+3696 
+1

Thanks :)

NotSoSmart  Dec 29, 2017
 #8
avatar+91215 
+1

25.  We have this equation

 

y  =  497 (1/2)x/38    where  y is the amount remaining after x  days have elapsed

 

[ This is the first answer ]

 

After 4 days have elapsed, the amt remaining is

 

497(1/2)4/38  ≈  462.06  kg

 

 

26.    log 4 1024

 

We can use the change-of-base theorem, here

 

The answer is given by :

 

log 1024  /  log 4   =   

 

5

 

 

cool cool cool

CPhill  Dec 29, 2017

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