#8**+1 **

25. We have this equation

y = 497 (1/2)^{x/38} where y is the amount remaining after x days have elapsed

[ This is the first answer ]

After 4 days have elapsed, the amt remaining is

497(1/2)^{4/38} ≈ 462.06 kg

26. log _{4} 1024

We can use the change-of-base theorem, here

The answer is given by :

log 1024 / log 4 =

5

CPhill Dec 29, 2017