+4116 Lol i'm waiting for CPhill.. he'll know how to explain it down to me.
+129849 25. We have this equation
y = 497 (1/2)x/38 where y is the amount remaining after x days have elapsed
[ This is the first answer ]
After 4 days have elapsed, the amt remaining is
497(1/2)4/38 ≈ 462.06 kg
26. log 4 1024
We can use the change-of-base theorem, here
The answer is given by :
log 1024 / log 4 =
5
