Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a radius of 7 feet and a height of 10 feet. Container B has a radius of 6 feet and a height of 14 feet. Container A is full of water and the water is pumped into Container B until Container A is empty.

After the pumping is complete, what is the volume of water in Container B, to the nearest tenth of a cubic foot?

 Jan 31, 2020




Hi there...


I have to be honest here.

That sounds like a trick question of sorts.

Kind of like the scenario, "You have 1kg of feathers and 1kg of iron. Which is the heaviest of the two?".


With that said...
Calculating the volume of "Container/Tank A" will give you the answer.
Seeing that it's the same amount of water you pump from A to B.
It doesn't matter if "Container/Tank B" happens to have a slightly larger total volume than "Container/Tank A", 'cause the amount of water stays pretty much the same.

The other way around, however, that would make a mess.



You have two jugs, A and B.
Jug A can room 1 Liter of water.
Jug B can room 2 Liter of water.

You fill "Jug A" up to the 1L-mark.
You then pour the water over into "Jug B".

How much water is now in "Jug B"?
The answer should be fairly obvious...

I hope that helped a bit?

Kind regards





 Jan 31, 2020
edited by BizzyX  Jan 31, 2020
edited by BizzyX  Jan 31, 2020

Volume of Container A:  V  =  pi·r2·h     --->     V  =  pi·72·10     --->     V  =  490·pi

Volume of Container B:                          --->     V  =  pi·62·14     --->     V  =  504·pi


Volume of air in Container B after the water in Container A is poured into Container B: 

     V  =  504·pi - 490·pi  =  ________          [the answer]

 Jan 31, 2020

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