How many three-digit perfect cubes are divisible by 9
Three digit perfect cubes =
5^3 = 125
6^3 = 216 = (6 * 6 * 6) = (3 * 2) (3* 2) (3* 2) = ( 3^3 * 2^3) = (3^2) * 3 * 2^3 = 9 * 24
7^3 = 343
8^2 = 512
9^3 = 729 = 9^3
So....216 and 729
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