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How many three-digit perfect cubes are divisible by 9

 Apr 7, 2020
 #1
avatar+111329 
+2

Three digit perfect  cubes = 

 

5^3  = 125

6^3 =  216 =  (6 * 6 * 6)  = (3 * 2) (3* 2) (3* 2)  =  ( 3^3 * 2^3) =    (3^2) * 3 * 2^3  =  9 * 24

7^3  = 343

8^2 =  512

9^3  = 729 =  9^3

 

So....216   and 729

 

 

cool cool cool

 Apr 7, 2020
 #2
avatar+201 
+1

THANKS!

 Apr 7, 2020

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