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# Help

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Evaluate $\left\lfloor \left\lceil \left(\frac{13}{7}\right)^2\right\rceil+\frac{17}{4}\right\rfloor$.

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Feb 4, 2021

#1
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I'm sorry about the formatting, I keep telling myself that I will learn latex, but I've been procrastinating.

floor(ceil((13/7)^2)+17/4)

floor(ceil(169/49)+17/4)

floor(4+17/4)

8

I hope this helped. :)))

=^._.^=

Feb 4, 2021
#2
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That's OK. I will do the translation for you.

$$\left\lfloor \left\lceil \left(\frac{13}{7}\right)^2\right\rceil+\frac{17}{4}\right\rfloor = \left\lfloor \left\lceil{\frac{169}{49}} \right\rceil + \frac{17}{4} \right\rfloor \\ \left\lfloor \left\lceil \left(\frac{13}{7}\right)^2\right\rceil+\frac{17}{4}\right\rfloor = \left\lfloor 4 + \frac{17}{4} \right\rfloor\\ \left\lfloor \left\lceil \left(\frac{13}{7}\right)^2\right\rceil+\frac{17}{4}\right\rfloor = 8$$

Guest Feb 4, 2021
#3
+425
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Thanks for translating. :)))

=^._.^=

catmg  Feb 5, 2021