+0  
 
+2
42
3
avatar+149 

Find all real numbers x such that 3x - 7\(\le\) 5x + 9. Give your answer as an interval.

Logic  Aug 25, 2018
 #1
avatar+599 
+1

Bringing x, and the numbers to one side, we get: \(-7-9\leq5x-3x=-16\leq2x\), so x is greater than or equal to -8. Try to see how you can form an interval.

[-8, infinity)

mathtoo  Aug 25, 2018
edited by mathtoo  Aug 25, 2018
 #2
avatar+343 
+1

\( 3x - 7≤5x + 9\) is our equation, and we want to move all the variables to one side. We can simplify the equation to  \( -2x ≤ 16\). Then, we need to divide each side by \(-2\). Since we are dividing/multiplying the equation by a negative number, we need to flip the sign. By doing this, we get \(x ≥ -8\). Since the problem is asking for an interval, we can get \([-8, +∞]\). Please correct me if I made a mistake!

 

- Daisy

dierdurst  Aug 25, 2018
 #3
avatar
+1

it did not work

Guest Aug 27, 2018

9 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.