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# Help

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Find all real numbers x such that 3x - 7$$\le$$ 5x + 9. Give your answer as an interval.

Aug 25, 2018

#1
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Bringing x, and the numbers to one side, we get: $$-7-9\leq5x-3x=-16\leq2x$$, so x is greater than or equal to -8. Try to see how you can form an interval.

[-8, infinity)

Aug 25, 2018
edited by mathtoo  Aug 25, 2018
#2
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$$3x - 7≤5x + 9$$ is our equation, and we want to move all the variables to one side. We can simplify the equation to  $$-2x ≤ 16$$. Then, we need to divide each side by $$-2$$. Since we are dividing/multiplying the equation by a negative number, we need to flip the sign. By doing this, we get $$x ≥ -8$$. Since the problem is asking for an interval, we can get $$[-8, +∞]$$. Please correct me if I made a mistake!

- Daisy

Aug 25, 2018
#3
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it did not work

Guest Aug 27, 2018