The roots of the quadratic equation 3x²-kx+14=0 are in the ratio 7:6, then k equals?
+9519 This means that
\(\begin{cases}\text{sum of roots} = \dfrac k3\\\text{product of roots} = \dfrac{14}3\end{cases}\)
Let the roots be 7p and 6p. Using the second formula,
\((7p)(6p) = \dfrac{14}3\\ p^2 = \dfrac19\\ p = \pm \dfrac13\)
Using the first formula,
\(13p = \dfrac k3\\ k = 39p = \pm13\)
