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If   a,b,c,x,y,z   are positive and x2+y2+z2=36,  and ax+by+cz=30, compute

 

a+b+cx+y+z
 

 Aug 9, 2019
 #1
avatar+6251 
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well.... if this is true for all a,b,c,x,y,z, then I can choose (x,y,z)=23(1,1,1)(a,b,c)(x,y,z)=3023(a+b+c)=30(a+b+c)=53x+y+z=63a+b+cx+y+z=5363=56

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 Aug 10, 2019

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