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# help

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The graph of x^2/a^2 + y^2/b^2 = 1 has its foci at (0, +/- 4), while the graph of x^2/a^2 - y^2/b^2 =1 has foci at (+/-6, 0). Compute the value |ab|.

I have just put it into Latex to make it easier to read. - Melody.

$$\text{The graph of } \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \text{ has its foci at }(0, \pm 4), \\~\\ \text{ while the graph of } \frac{x^2}{a^2}- \frac{y^2}{b^2} =1 \text{ has foci at }(\pm6, 0).\\~\\ \text{Compute the value }|ab|.$$

Coding.

\text{The graph of } \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \text{has its foci at }(0, \pm 4)\\ \text{, while the graph of } \frac{x^2}{a^2}- \frac{y^2}{b^2} =1 \text{ has foci at }(\pm6, 0).\\ \text{Compute the value }|ab|.

Dec 7, 2019
edited by Melody  Dec 7, 2019

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+5

As follows:

Dec 7, 2019