Evaluate c-2c−2c, minus, 2 when c=7c=7
I'm not sure what that means. I'm going to assume that the equation is \(c-2c-2c-2\)and
\(c=7\)
We just substitute c:
\(c-2c-2c-2=7-2\times7-2\times7-2=7-2=\boxed{5}\), so the answer is 5.
