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Evaluate c-2c−2c, minus, 2 when c=7c=7

Guest Sep 18, 2017
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I'm not sure what that means. I'm going to assume that the equation is \(c-2c-2c-2\)and 

\(c=7\)

 

We just substitute c:

 

\(c-2c-2c-2=7-2\times7-2\times7-2=7-2=\boxed{5}\), so the answer is 5.

 

laugh​​laugh​​laugh​​

Jeff123  Sep 18, 2017

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