The sum of four consecutive integers is n. Find the largest integer, in terms of n.
9996 + 9997 + 9998 + 9999 = 39,990
let each integer be z
z,z+1,z+2,z+3 are 4 consecutive integers
Their sum is equal to n
z+z+1+z+2+z+3=4z+6=n
Well largest integer in terms of n is
n=4z+6
