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Find the smallest number that is divisible by 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10.

 Jun 24, 2020
 #1
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so it basicaly asks to find the least common multiple, so first we should try to factor everything.

 

1-1

2-2

3-3

4-2*2

5-5

6-2*3

7-7

8-2*2*2

9-3*3

10-2*5

 

So the number must have atleast 3 2's, 2 3's, a 5 and a 7

so from here (2^3)*(3^2)*5*7=8*6*5*7=1680

 Jun 24, 2020
 #2
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+1

LCM(1,2,3,4,5,6,7,8,9,10) = 2,520

 Jun 24, 2020

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