What are the rectangular coordinates of the polar coordinates (3√2,−π/6) ?
x = 3√2 cos (-pi/6) = 3√2 * √3/2 = (3/2)√6
y = 3√2 sin (-pi/6) = 3√2 * (-1/2) = -3√2 / 2 = -(3/2)√2
So
(x , y) = ( (3/2)√6 , -(3/2)√2 )