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# Help

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1.) It takes max three times as long as Felix to complete the same job. When the men work together, they can complete the job in 9 hours. how many hours are required for max to do the job alone?

2.) Solve the equation [x] / [x-2] =  / [x^2-8x+12]  -  / [x-6]

which statements are true of the solutions(s) to the equation?

a.) there are two accecptable soutions to the equation.

b.) There are no accecptable solutions to the equation.

c.) 6 is an extraneous solution because it creates a 0 in the denominator

d.) there is one acceptable solution to the equation

e.) 2 is an extraneous solution because it creates a 0 in the denominator.

Oct 19, 2018

#1
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1.) It takes max three times as long as Felix to complete the same job. When the men work together, they can complete the job in 9 hours. how many hours are required for max to do the job alone?

Let  the portion of the job that Felix can complete in one hour  =  1/x

Let the portion of the job that Max can complete in one hour  =  1 / [3x]

So.....  rate * time  =  potion of job done....so

Portion that Felix can do in 9 hours  + portion that Max can do in 9 hrs  =  1 job done

(1/x) (9)  +  ( 1 / [3x] )  (9)  =  1

9/x  +  3/x  =  1

12/x  =  1

x = 12  means that Felix can complete the whole job in 12 hours working alone

So..Max can complete the job  in 3(12)  =  36 hours working alone   Oct 19, 2018
#2
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2.) Solve the equation [x] / [x-2] =  / [x^2-8x+12]  -  / [x-6]

x / [ x - 2]   = 4 / [ ( x -6 ) ( x - 2) ]  - 1/ (x - 6)

Multiply through by  (x - 6) ( x - 2)

x ( x - 6)   =  4  - ( x - 2 )   simpify

x^2 - 6x  = 4 - x + 2

x^2 - 6x = 6 - x

x^2 - 5x - 6  =  0     factor

( x - 6) ( x + 1)  =  0      set both factors to 0   and solve for x and we have that

x = 6     or  x  =  -1

The first solution  makes a denominator  =  0....so it is extraneous

So.....

c.) 6 is an extraneous solution because it creates a 0 in the denominator

d.) there is one acceptable solution to the equation   Oct 19, 2018