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avatar+54 

(w+64)/ (4+w)

How do I solve?

needmathhelp  Apr 6, 2017
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3+0 Answers

 #1
avatar+79819 
+2

There's nothing to solve......we can just simplify

 

( w^3 + 64) / (4 + w)  

 

Factor the numerator as a sum of cubes

 

[ (w + 4) (w^2  - 4w + 16) ] / (w + 4)  =

 

w^2 - 4w + 16 

 

 

 

cool cool cool

CPhill  Apr 6, 2017
 #2
avatar+54 
0

what about this one? (4g 2 - 9) รท (2g - 3

needmathhelp  Apr 6, 2017
 #3
avatar+79819 
+2

[ 4g^2 - 9 ] / [2g - 3]

 

Factor the numerator as a difference of squares

 

[ (2g + 3) (2g - 3) ] / (2g - 3)   =

 

2g + 3

 

 

cool cool cool

CPhill  Apr 6, 2017

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