(w3 +64)/ (4+w)
How do I solve?
There's nothing to solve......we can just simplify
( w^3 + 64) / (4 + w)
Factor the numerator as a sum of cubes
[ (w + 4) (w^2 - 4w + 16) ] / (w + 4) =
w^2 - 4w + 16
what about this one? (4g 2 - 9) ÷ (2g - 3
[ 4g^2 - 9 ] / [2g - 3]
Factor the numerator as a difference of squares
[ (2g + 3) (2g - 3) ] / (2g - 3) =
2g + 3
