show that the circle x2+y2-16x-20y+115=0 and x2+y2+8x-10y+5=0 are tangent .
+36916 Find the centers of the circles
x^2-16x +64 +y^2 -20 y +100 +115 -64 -100 = 0
(x-8)^2 + (y-10)^2 = 49
center (8,10) radius = 7
x^2+8x + 16 + y^2-10y +25 +5 -16-25 =0
(x+4)^2 + (y-5)^2 = 36
center (-4,5) radius = 6
Does the distance between the centers = the radii combined? If so, they are tangent...
d^2 = (8--4)^2 + (10-5)^2
144 + 25
d = 13 radii = 6+7 = 13 Yeas they are tangent....they touch at one point.
+36916 Find the centers of the circles
x^2-16x +64 +y^2 -20 y +100 +115 -64 -100 = 0
(x-8)^2 + (y-10)^2 = 49
center (8,10) radius = 7
x^2+8x + 16 + y^2-10y +25 +5 -16-25 =0
(x+4)^2 + (y-5)^2 = 36
center (-4,5) radius = 6
Does the distance between the centers = the radii combined? If so, they are tangent...
d^2 = (8--4)^2 + (10-5)^2
144 + 25
d = 13 radii = 6+7 = 13 Yeas they are tangent....they touch at one point.
