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avatar+191 

Suppose 2 distinct integers are chosen from 1 through 9, inclusive. What is the probability that they are both odd?

Lightning  Mar 16, 2018
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3+0 Answers

 #1
avatar+12247 
-1

5 odds  4 evens

 

5 out of 9   to be odd on first   and  5 out of 9 for the second   5/9 x 5/9 = 25/81

(this assumes all of the 1-9 numbers are available both draws)

ElectricPavlov  Mar 16, 2018
 #2
avatar+85821 
+3

We have  5 odd integers....

 

P (both odd)   =  5/9  * 4/8    =    5/9 * 1/2   =   5/18

 

The guest has assumed replacement......my answer  assumes without replacement

 

 

cool cool cool

CPhill  Mar 16, 2018
edited by CPhill  Mar 16, 2018
 #3
avatar+191 
+1

@CPhill You are correct. Thank you!

Lightning  Mar 17, 2018
edited by Lightning  Mar 17, 2018

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