Help!

Question

+1

983

3

+1242

Suppose 2 distinct integers are chosen from 1 through 9, inclusive. What is the probability that they are both odd?

Lightning Mar 16, 2018

ElectricPavlov · Answer 1 · 2018-03-16T11:11:06

5 odds 4 evens

5 out of 9 to be odd on first and 5 out of 9 for the second 5/9 x 5/9 = 25/81

(this assumes all of the 1-9 numbers are available both draws)

CPhill · Answer 2 · 2018-03-16T11:12:04

We have 5 odd integers....

P (both odd) = 5/9 * 4/8 = 5/9 * 1/2 = 5/18

The guest has assumed replacement......my answer assumes without replacement

Lightning · Answer 3 · 2018-03-17T05:38:13

@CPhill You are correct. Thank you!