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In 432 B.C., part of the Greek city of Olynthus was divided into rectangular city blocks measuring 120 feet by 300 feet. To the nearest foot, what Is the diagonal distance across each city block?

 Oct 20, 2016
edited by Guest  Oct 20, 2016
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120^2 + 300^2 = x^2

 

x is the answer

 Oct 20, 2016

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