The points (-3, 2) and (-2, 3) lie on a circle whose center is on the x-axis. What is the radius of the circle?

Guest Nov 3, 2019

#1**+3 **

Standard equation of a circle

(x – h)^{2} + (y – k)^{2} = r^{2}

^{With (h, k) being your center coordinates.}

If a circle with a center is on the x-ais, then its k-value is zero.

So plugging in our two coordinates into the standard equation:

\((-3-h)^2+(2)^2=r^2\)

\((-2-h)^2+(3)^2=r^2\)

Can you solve from here?

CalculatorUser Nov 3, 2019