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The points (-3, 2) and (-2, 3) lie on a circle whose center is on the x-axis. What is the radius of the circle?

 Nov 3, 2019
 #1
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Standard equation of a circle

 

(x – h)2 + (y – k)2 = r2

 

With (h, k) being your center coordinates.

 

If a circle with a center is on the x-ais, then its k-value is zero.

 

So plugging in our two coordinates into the standard equation:

 

\((-3-h)^2+(2)^2=r^2\)

 

\((-2-h)^2+(3)^2=r^2\)

 

 

 

Can you solve from here?

 Nov 3, 2019

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