The points (-3, 2) and (-2, 3) lie on a circle whose center is on the x-axis. What is the radius of the circle?
+2862 Standard equation of a circle
(x – h)2 + (y – k)2 = r2
With (h, k) being your center coordinates.
If a circle with a center is on the x-ais, then its k-value is zero.
So plugging in our two coordinates into the standard equation:
\((-3-h)^2+(2)^2=r^2\)
\((-2-h)^2+(3)^2=r^2\)
Can you solve from here?
