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Three of the four vertices of a rectangle are ,(5, 11) (16, 11)  and .(16, -2) What is the area of the intersection of this rectangular region and the region inside the graph of the equation ? Express your answer in terms of .(x - 5)^2 + (y + 2)^2 = 9

 Mar 6, 2020
 #1
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Also, you need to express your answer in terms of pi.

 Mar 6, 2020
 #2
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The fourth vertex is (5, -2) which is also the center of the circle.

The circle has radius 3 and the overlap of the circle and the rectangle is one-fourth of the circle.

(1/4) · pi · radius2  =  (1/4) · pi · 32  =  9·pi/4

 Mar 6, 2020

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