Let \(f(x)=\frac{(x-2)^2-9}{3}\). The equation y=f(x) is graphed, and the x and y-intercepts of the graph are connected to form a polygon. What is the area of that polygon?
+23245 The x-intercepts occur at (-1,0) and (5,0).
The y-intercept occurs at (0,-5/3).
The figure is a triangle with base from (-1,0) to (5,0) -- a base length of 6.
The height is from (0,0) to (0,-5/3) - a height of 5/3
Use the area formula for a triangle: A = ½·base·height to find the area
