If each hen can lay 2 eggs in 3 days, how many days are needed for 4 hens together to play 2 dozen eggs?
+47 \(h_e = T(3)C_e(2)\)
Singular hen:
\(h= {E_1\over 1.5(12H)}\)
Total between 4 hens:
\(Total_i = {24\over C_h(4)} \)
Individual threshold:
\(6\)
Time for individual completion:
\(6=3_d({I_t\over C_e[2]})\)
Answer:
\(9\space days\)
