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At a supermarket, 1/2 of the kiwifruits and 1/7 of the strawberries were rotten. The ratio of the total number of strawberries were rotten. The ratio of the total number of strawberries to the number of kiwifruits was 7:3. If there was 245 rotten kiwifruits and strawberries, how many kiwifruits and strawberries were there altogether?

 Aug 18, 2022
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K==Kiwis,   S==Strawberries

 

(1/2)K + (1/7)S==245.........................(1)   

S / K ==7 / 3.......................................(2),  solve for K, S

 

K ==294 Kiwifruits

S ==686 strawberries

 

294 + 686 ==980 kiwisfruits and strawberries altogether.

 Aug 18, 2022

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