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If the following infinite series S is evaluated as a decimal,what is the 37th digit to the right of the decimal place?

 

\(\large S=\frac { 1 }{ 9 } +\frac { 1 }{ 99 } +\frac { 1 }{ 999 } +\ldots + \frac { 1 }{ { 10 }^{ n }-1 } + \ldots\)

 Jun 15, 2020
 #1
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S=0.1223242434262445262644283446282644492. 37th digit is 2

 Jun 15, 2020

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