#1**+5 **

"*Find all values of x that satisfy 6(x + 1/x)^2 - 35(x + 1/x) + 50 = 0.*"

First let y = x + 1/x. Then we have 6y^2 -35y + 50 = 0 Solve this using the quadratic equation, to get two values of y.

Then set x + 1/x equal to each value of y in turn, multiply through by x each time to get another quadratic (this time in x) and solve for x.

You will get four values of x in total.

Alan Dec 15, 2019

#1**+5 **

Best Answer

"*Find all values of x that satisfy 6(x + 1/x)^2 - 35(x + 1/x) + 50 = 0.*"

First let y = x + 1/x. Then we have 6y^2 -35y + 50 = 0 Solve this using the quadratic equation, to get two values of y.

Then set x + 1/x equal to each value of y in turn, multiply through by x each time to get another quadratic (this time in x) and solve for x.

You will get four values of x in total.

Alan Dec 15, 2019