A standard six-sided die is rolled 6 times. You are told that among the rolls, there was one 1, 2 two's, and 3 three 's. How many possible sequences of rolls could there have been? (For example, 323132 is one possible sequence.)
6! / (1! 2! 3!) = (6*5*4)/(2)=6*5*2=60
Nice :))
I got sniped.
=^._.^=
Thank you, catmg! :)
Thanks!
