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A standard six-sided die is rolled 6 times. You are told that among the rolls, there was one 1, 2 two's, and 3 three 's. How many possible sequences of rolls could there have been? (For example, 323132 is one possible sequence.)

 May 8, 2021

Best Answer 

 #1
avatar+781 
+3

6! / (1! 2! 3!) = (6*5*4)/(2)=6*5*2=60

edited by MathProblemSolver101  May 8, 2021
 #1
avatar+781 
+3
Best Answer

6! / (1! 2! 3!) = (6*5*4)/(2)=6*5*2=60

edited by MathProblemSolver101  May 8, 2021
 #2
avatar+2209 
+3

Nice :))

I got sniped. 

 

=^._.^=

catmg  May 8, 2021
 #3
avatar+781 
+2

Thank you, catmg! :)

 #4
avatar
0

Thanks!

Guest May 8, 2021

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