How much pure acid should be mixed with 5 gallons of a 50% acid solution in order to get an 80% acid solution?
+36916 100% x + 50% (5) = 80% (x+5)
1.0x +.5(5) = .8(x+5) solve for x the number of gallons of 100% acid to use,....
+36916 100% x + 50% (5) = 80% (x+5)
1.0x +.5(5) = .8(x+5) solve for x the number of gallons of 100% acid to use,....
