There is a total of 20 quarters stacked in four piles. The first pile has 3 fewer than the second pile. The second pile has 2 more than the third pile. The fourth pile has twice as many as the second pile. How many quarters are in the fourth pile?
Let the the 3rd pile =T The 2nd pile =T + 2 First pile =[T - 1] Fourth pile =2[T + 2] T + T + 2 + T - 1 + 2T + 4 =20, solve for T 5T + 5 = 20 5T = 15 T =3 quarters - 3rd pile 3+2 =5 quarters- 2nd pile 3-1 =2 quarters- 1st pile. 5 x 2=10 quarters - 4th pile
