X and Y departed from a town together for another town 45 km away. If the speed of X is 1 km/h more than that of Y, he reaches his destination half an hour earlier than Y. Find the speed of X and Y.
+36914 rate x time = d
rates x and x+1 time t1 and t1-1/2 (1/2 hr = 30 minutes)
x(t1) = 45 or t1 = 45/x
and
(x+1)(t1-1/2) = 45
(x+1)(45/x-1/2) = 45
45 -1/2x + 45/x-1/2 = 45
-1/2x + 45/x -1/2 = 0
-1/2x^2 -1/2x +45 = 0 x = 9 km/hr from Quadratic formula then t1 = 45/9 =5 hr x+1 = 10 km/hr
