X and Y departed from a town together for another town 45 km away. If the speed of X is 1 km/h more than that of Y, he reaches his destination half an hour earlier than Y. Find the speed of X and Y.

Guest Jun 27, 2020

#1**+1 **

rate x time = d

rates x and x+1 time t1 and t1-1/2 (1/2 hr = 30 minutes)

x(t1) = 45 or t1 = 45/x

and

(x+1)(t1-1/2) = 45

(x+1)(45/x-1/2) = 45

45 -1/2x + 45/x-1/2 = 45

-1/2x + 45/x -1/2 = 0

-1/2x^2 -1/2x +45 = 0 x = 9 km/hr from Quadratic formula then t1 = 45/9 =5 hr x+1 = 10 km/hr

ElectricPavlov Jun 28, 2020