Three of the four vertices of a rectangle are $(5, 11)$, $(16, 11)$ and $(16, -2)$. What is the area of the intersection of this rectangular region and the region inside the graph of the equation $(x - 5)^2 + (y + 2)^2 = 9$? Express your answer as a common fraction in terms of pi.

Guest Jan 15, 2018

The other vertex  of the rectangle is  the circle's center  =   (5, -2)


Look  at the image here :  



The region common to both areas is just  the quarter circle  area  of the given circle


And this circle has a radius  of 3.....so....the quarter circle has an area  of


pi (r^2)  / 4  =   pi (3^2)  / 4  =    (9/4)pi   units ^2



cool cool cool

CPhill  Jan 15, 2018

13 Online Users


New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.