If a range hood removes contaminants at a flow rate of F liters of air per second, then the percent P of contaminants that are also removed from the surrounding air can be modeled by P=1.14F+18.31, where F is between and inclusive of 10 and 75. What flow rate F a range hood have to remove 85 % of the contaminants from the air? The hood must have a flow rate F of about _____ liters of air per second.
(Simplify your answer. Round to the nearest integer as needed.)
P = 1.14F + 18.31 and 10 ≤ F ≤ 75
The question is.....what value of F causes P to be 85 ?
Plug in 85 for P and solve for F .
85 = 1.14F + 18.31 Subtract 18.31 from both sides.
66.69 = 1.14F Divide both sides by 1.14 .
58.5 = F This is between 10 and 75 , so it is a possible value for F .
The hood must have a flow rate of about 59 liters per second.
P = 1.14F + 18.31 and 10 ≤ F ≤ 75
The question is.....what value of F causes P to be 85 ?
Plug in 85 for P and solve for F .
85 = 1.14F + 18.31 Subtract 18.31 from both sides.
66.69 = 1.14F Divide both sides by 1.14 .
58.5 = F This is between 10 and 75 , so it is a possible value for F .
The hood must have a flow rate of about 59 liters per second.