How much work is required to change the velocity of a 2,100-kg car from
25 m/s to 15 m/s?
+37146 I THINK the work involved will be equal to the change in Kinetic Energy (1/2 m v^2 )
Original KE = 1/2 (2100)(25^2) = 656250
End KE = 1/2 (2100)(15^2)= 236250
Difference =420 kj
