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The polynomial f(x) has degree 3. If f(-1) = 15, f(0)= 0, f(1) = -5, and f(2) = 12, then what are the x-intercepts of the graph of f?

 Apr 10, 2019
 #1
avatar+6252 
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f(x)=ax3+bx2+cx+df(1)=a+bc+d=15f(0)=d=0f(1)=a+b+c+d=5f(2)=8a+4b+2c+d=12I like to use matrices, there are other ways to solve the following(111111842)(abc)=(15512)

 

Gaussian reducing this we get(abc)=(2512)

 

f(x)=2x3+5x212x=x(2x2+5x12)=x(2x3)(x+4)x intercepts at x{0, 32, 4}

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 Apr 10, 2019
 #2
avatar+283 
0

thanks!

 Apr 10, 2019

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