The polynomial f(x) has degree 3. If f(-1) = 15, f(0)= 0, f(1) = -5, and f(2) = 12, then what are the x-intercepts of the graph of f?
f(x)=ax3+bx2+cx+df(−1)=−a+b−c+d=15f(0)=d=0f(1)=a+b+c+d=−5f(2)=8a+4b+2c+d=12I like to use matrices, there are other ways to solve the following(−11−1111842)(abc)=(15−512)
Gaussian reducing this we get(abc)=(25−12)
f(x)=2x3+5x2−12x=x(2x2+5x−12)=x(2x−3)(x+4)x intercepts at x∈{0, 32, −4}
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