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Find the exact value under the given conditions

sin a = 20/29, 0 < a < π/2;

cosβ=12/13, 0 < β

 

find cos(a+β)

 May 27, 2020
 #1
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meant cosβ=12/13, 0 < β < π/2;

 May 27, 2020
 #2
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Find the exact value under the given conditions

sin a = 20/29, 0 < a < π/2;

cosβ=12/13, 0 < β

 

find cos(a+β)


Hello Guest!

\(cos(\alpha+\beta)=cos(arcsin(\frac{20}{29})+arccos(\frac{12}{13}))\)

\(cos(\alpha+\beta)=cos(0.761+0.3948)\)

\(cos(\alpha+\beta)=cos(1.1558)\)

\(cos(\alpha+\beta)=0.403183\)

laugh  !

 May 28, 2020

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