Help

0

664

1

Compute

\( (1 + i)(1 + 2i)(1 + 3i) \)

Guest May 5, 2019

0 users composing answers..

1⁺⁰ Answers

+9465

+3

	(	1 + i	)	(	1 + 2i	)	(	1 + 3i	)	____	Multiply ( 1 + i )( 1 + 2i ) then simplify.
=__	(	1 + 2i + i + 2i²				)	(	1 + 3i	)
=	(	1 + 3i - 2				)	(	1 + 3i	)
=	(	-1 + 3i				)	(	1 + 3i	)		Multiply ( -1 + 3i )( 1 + 3i ) then simplify.
=		-1 - 3i + 3i + 9i²
=		-1 - 9
=		-10

hectictar May 5, 2019

2 Online Users